Answers

2015-04-03T12:03:53+05:30
Cot Ф=4/3=base/prependiculat
hypo=5
ATQ..................
1+sinФ/1+cosФ  1-sinФ/1-cosФ
1+3/5        1-3/5
1+4/5        1-4/5

8/9 x 2/1=16/9
0
thank u so much
your welcome
mark as best
kk
2015-04-03T12:24:32+05:30
L.H.S 1+SinФ/1+CosФ *1-SinФ/1-CosФ ; 1-Sin^2Ф/1-Cos^2Ф [by identity sin^2Ф+ cos^2Ф=1] ; Cos^2Ф/Sin^2Ф ; Cot^2Ф ; (4/3)^2 ; 16/9
0