Answers

2015-04-04T12:52:00+05:30
given that ,
 ∠2 = ∠3 ( AP is a bisector ) 
const .
    draw M ⊥  on AP and join to AB on P and similarly in other side M ⊥ AP and join that to AC at Q . 
we get , 
  ∠1 = ∠4 =  90^{0}
To prove -  PM = QM
proof -  in Δ APM and Δ AMQ 
       ∠2 = ∠3 ( GIVEN  )
      AM = AM ( COMMON )
     ∠1 = ∠4 ( by const. )
 by ASA Δ APM congruent to Δ AMQ .
⇒ PM = QM ( C.P.C.T)
 
 
 
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