# Find the canvas required to make a covered cubicle of edge 8m,in a park.

2
by ashrut

• Brainly User
2015-04-04T20:23:01+05:30

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length of cube = 8m
total surface area = 6*l*l
= 6*8*8 m^2
= 384 m^2
the canvas required is 384 m^2

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There is mistake in your calculation ,it is 384 instead of 288m62
2015-04-04T20:34:22+05:30

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Given;
Length(l) of the cubicle=8 m.

The canvas required= total surface area of cube

=6l²
=6 x 8 x 8 m²
=6 x 64 m²
=384 m².

Hope i helped u:)