Answers

2015-04-06T01:04:08+05:30
Let ABCD be a rectangle.
We have to prove that AC = BD.

In the triangles ABC and DCB:

BC = CB (common)
 
AB = DC   (opposite sides of a parallelogram)
 
ABC
=DCA = 90°   (given)

so ABC ≡ DCB (SAS)

Hence AC = DB (matching sides of congruent triangles).

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