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How much enery is relased or observed when 1gm of ice at 0 cel turl into 1 gm of vapour at 100 cel

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1 gm of ice at 0 ⁰C to turn into 1 gm of vapour at 100 ⁰C

1) 1 gm of ice takes the latent heat of fusion to melt into water.

heat energy needed = 1 gm * 334 Joules/gm = 334 J

2) 1 gm of water heats up to 100°C as water

heat energy needed = mass * specific heat * temperature difference

= 1 gm * 4.18 J/gm/°C * 100°C = 418 Joules

3) 1 gm of water at 100°C changes physical state into vapour

heat energy needed = latent heat of vaporization

= 1 gm * 2260 J/gm = 2260 J

total energy absorbed by the water = 334 + 418 + 2260 = 3, 012 Joules

1) 1 gm of ice takes the latent heat of fusion to melt into water.

heat energy needed = 1 gm * 334 Joules/gm = 334 J

2) 1 gm of water heats up to 100°C as water

heat energy needed = mass * specific heat * temperature difference

= 1 gm * 4.18 J/gm/°C * 100°C = 418 Joules

3) 1 gm of water at 100°C changes physical state into vapour

heat energy needed = latent heat of vaporization

= 1 gm * 2260 J/gm = 2260 J

total energy absorbed by the water = 334 + 418 + 2260 = 3, 012 Joules