# Three resistors A,B,C are connected as shown in the figure.Each of them dissipates energy to maximum of 18 W .Find the maximum current that can flow through three resistors.

2
by safura

2015-04-10T11:42:11+05:30
Resistance B and C are connected in parallel then their resultant resistance is series with resistance A.all over resultant would be
1/Req=1/Rb+1/Rc
1/Req=1/2+1/2
Req=1Ω
This equivalent is series with A resistance
Rnet=Req+R(A)
Rnet=2+1=3Ω
As power=(Current)² Resistance
18=I²X3
I²=6 ,I=√6
I=2.2A current
welcome
which class you are in
18 watts is power dissipated by each and not the total.
2015-04-11T20:12:07+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
V= voltage across a resistor
I = current through the resistor
R = value of resistance.

Power  dissipated by the resistor is given by : P =  V²/R = I² R
I² = P / R

Each resistance dissipates energy = 18 Watts

Maximum current through B or C or A is given by : I² = 18 Watts/2 ohms
So I = 3 Amperes maximum

Since the resistances B and C are connected in parallel, the current that comes from the resistance A is divided equally between the resistance B and C.
so current through  B = current through resistance C = 1/2 * current thru A

Since, the current passing thru resistor A is max = 3 ampere, then the current through resistor B and resistor C  are 1.5 Amperes maximum.

In which class you are?