Answers

The Brainliest Answer!
2014-04-26T10:59:46+05:30
log_{4}(x-1)=log_{2}(x-3) \\  \frac{1}{2}log_{2}(x-1)=log_{2}(x-3) \\ log_{2}(x-1)=log_{2}(x-3)^2
x-1=(x-3)^2=x^2-6x+9 \\ x^2-7x+10=0 \\ (x-2)(x-5)=0
since 2-3=-1 x cannot be 2 as logâ‚‚ (-1) is not defined
so x=5 only
1 5 1
well u are not so stupid by the way
does my answer help u..
so log2 (7) is an .......?
well it is an irrationa number
good