A stone is thrown in a vertically upward direction with a velocity of 5 m s(power -1). if the acceleration of the stone during its motion is 10 m s(power -2) in the downward direction , what will be the height attained by the stone and how much time will it take to reach there? With steps plse..

1
by hrithi

2015-04-14T23:22:39+05:30

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U = initial velocity = 5 m/sec    is in the upward direction
a = - 10 m/sec²                is in the down ward direction.  so it is negative.

when the stone reaches the maximum height, its velocity v = 0 m/sec.  Then it starts to fall back  on the ground.

equation of motion:     v² = u² + 2 a s
0 = 5² - 2 * 10 *  s
s =  25/20 = 1.25 meters

v =  u  +  a  t
0 =  5  -  10 * t
t  =  0.5 seconds

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