A stone is thrown in a vertically upward direction with a velocity of 5 m s(power -1). if the acceleration of the stone during its motion is 10 m s(power -2) in the downward direction , what will be the height attained by the stone and how much time will it take to reach there? With steps plse..

1

Answers

The Brainliest Answer!
2015-04-14T23:22:39+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
U = initial velocity = 5 m/sec    is in the upward direction
a = - 10 m/sec²                is in the down ward direction.  so it is negative.

when the stone reaches the maximum height, its velocity v = 0 m/sec.  Then it starts to fall back  on the ground.

 equation of motion:     v² = u² + 2 a s
           0 = 5² - 2 * 10 *  s
             s =  25/20 = 1.25 meters
 
         v =  u  +  a  t
           0 =  5  -  10 * t
             t  =  0.5 seconds

3 5 3
click on thank you button (blue) above pls