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The Brainliest Answer!
2015-04-15T14:48:06+05:30
 \sqrt{4 a^{2} } = 2a
\sqrt{4} \sqrt{a^{2}  } = 2a
2 × a = 2a
therefore it is true
 \sqrt{ a^{2}+4 } =a+2
 \sqrt{ a^{2}+ 2^{2}  } =a+2
 \sqrt{ a^{2}+ a^{2}  }  \neq a+2
threfore it is false

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