Answers

2014-01-18T14:47:31+05:30
1) Using the division method, we'll notice that if we add the digits from the number 10404 = 1+0+4+0+4=9 which is divisible by 3, so we could write as:10404 = 3*3468We'll verify if the sum of the digits of the number 3468 is divisible by 3:3468 = 3+4+6+8=2110404 = 3*3*1156Because the sum of the digits of the number 1156 is not divisible by 3, but the number is ending in a digit which is divisible by 2, we'll divide the number 1156 by 2:10404 = 3*3*2*578Again, 578 is divisible by 2:10404 = 3*3*2*2*289We notice that 289 = 17*17So the number 10404 could be written as:10404 = 2^2*3^2*17^2sqrt10404 = sqrt(2^2)*sqrt(3^2)*sqrt(17^2)sqrt 10404 = 2*3*17sqrt 10404 = 102
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