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2015-04-15T22:07:49+05:30

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Mass  m =  1 gm
pressure P = 1 atm
volume V = 1,671 cm³
Let the absolute temperature of water be = T ⁰K

   Using the ideal gas law:    P V = n R T
             1.013 * 10^5 * 1,671 * 10⁻⁶ = 1/18 mole * 8.314 J/⁰K/mole * T
                  T = 366.48⁰K

work done in expansion of the vapour from 1 cm³ water to 1671 cm³ vapour: at 1 atm. pressure:   P (V2 - V1) = 1.013 * 10⁵ N/m² * (1671-1) * 10⁻⁶ m³
           = 169.17 Joules = 169.17/4.184  cal = 40.43 Cal

Latent heat of vapourization = 540 cal / gm = 2257 J/gm

The increase in the internal energy = latent heat -  work done in expansion
                   = 540 cal - 40.43 cal = 500 cal  nearly.

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