Answers

2015-04-16T20:21:34+05:30
A^2 - 3a - 1 = 0

Solve the quadratic equation

=> a = (3 + sqrt(13) ) / 2 AND (3 - sqrt(13) ) / 2

Also 1 / a = (sqrt(13) - 3) / 2 AND - (3 + sqrt(13) ) / 2

So, a^2 + 1/a^2 = ( (3 + sqrt(13) )^2 + (3 - sqrt(13) )^2 ) / 4 = (9+13) / 2 = 22/2 = 11

Ans, 11
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