Answers

2014-04-29T08:18:20+05:30
As ,b and c are in A.P
2b=a+c
and
 \frac{1}{ab}+ \frac{1}{bc}= \frac{b(a+c)}{ab(bc)}= \frac{a+c}{abc}= \frac{2b}{abc}= \frac{2}{ca}
so
 \frac{1}{bc}, \frac{1}{ca}, \frac{1}{ab}   are in A.P
then
a+ \frac{1}{bc},b+ \frac{1}{ca},c+ \frac{1}{ab}
are in A.P
as sum of two A.P's is in an A.P
1 5 1