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## Answers

P(x=3)>p(x=2)

(e^-lamda d^2)/3! > (e^-lamda lamda^2)/ 2!

henece d= 3

mean = 3

(e^-lamda d^2)/3! > (e^-lamda lamda^2)/ 2!

henece d= 3

mean = 3

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P(x=3)>p(x=2)

(e^-lamda d^2)/3! > (e^-lamda lamda^2)/ 2!

henece d= 3

mean = 3

(e^-lamda d^2)/3! > (e^-lamda lamda^2)/ 2!

henece d= 3

mean = 3