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2015-04-18T17:12:09+05:30

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(a-1)\sqrt{2}+3~=~b\sqrt{2}+a

Since a,b are rational and \sqrt{2} is irrational, we can compare rational and irrational terms both sides. Comparing terms attached to \sqrt{2} both sides we get :
a-1=b

comparing rational terms both sides gives
3=a

Plug this in the earlier equation and get
3-1=b\implies\,b=2

1 5 1
sir pleas explain it because i can't understand
updated, please see if it makes sense now
thanks and i do this.
sounds good