# An elevator descends into a mine shaft at the rate of 7m per minute .If it descent starts from 20 m above the ground level ,find the time taken by the elevator to reach -400m.

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by amna

## Answers

2015-04-19T11:30:38+05:30

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Starting value :
rate :

setup an equation and solve
minutes
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2015-04-19T11:30:50+05:30

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The elevator starts from 20 m above the ground.
Therefore , total distance to be covered=(400+20)m=420 m.
Speed=7 m/min.
Therefore, time=D/S
=420/7 min
=60 min
=1 hr
Ans>The time taken is 1 hour.
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