# The amount of heat required to convert 1gm of ice at 0 degree centigrade into steam at 100 degrees centigrade is .......[L ice=80,Sw=1,L steam=540]

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by suchana

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by suchana

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The Brainliest Answer!

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Whereas "Latent-Heat" is the amount of heat required to change the phase of a unit mass of substance.

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Now for the phase change from solid-ice to liquid-water, heat required is

(1 gm)(80 cal/gm) = 80 cal.

To raise the temperature of water from 0 to 100 (celsius), heat required is

(1 gm)(1 cal/gm/K)(100 K) = 100 cal.

Again for the phase change from liquid-water to gaseous-steam, heat required is

(1 gm)(540 cal/gm) = 540 cal.

Summing up the entire thing you get, total heat required = 720 cal = 0.72 kcal.