# If alpha and beta are the zeroes of the quadratic polynomial p(x)=ax2+bx+c then evaluate alpha square beta+alpha betasq

2
by jeffijoshna

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by jeffijoshna

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The Brainliest Answer!

alpha+beta=-b/a

alpha*beta=c/a

Therefore,alpha sq.+beta sq. =(alpha+beta)^2-2.alpha.beta

=(-b/a)^2-2*c/a

=b^2/a^2-2c/a

=(b^2-2ac)/a^2

As α and β are the roots

and u know

α+β=-b/a

αβ=c/a

α²+β²=(α+β)²-2αβ=

and u know

α+β=-b/a

αβ=c/a

α²+β²=(α+β)²-2αβ=