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2015-04-22T11:48:36+05:30

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    This is not solvable in the normal arithmetic method of addition of the numbers given.  We have to have three even numbers, OR  one even number and two odd numbers to get the result as an even number.  But we don’t have any even number in the given set of numbers in the parentheses.

     We need to use an operator like  a factorial or some other one, which yields an even number taking an odd number as the input.  Logarithm is an operator or a function which also can give an even number.

   It is left to imaginative skill and knowledge of the person to answer this question.

     3!   +  11  + 13    = 30

     15 + 15 + Log 1  = 30          ,  as Log 1 = 0  to any base.
    
15 + 15 + Ln 1  = 30          ,  as Ln 1 = 0  to any base

      3*7 + 9 + Log 1  = 30
     15  +  13  + 3!/3  = 30
     (1+3)! + 1 +  5    = 30
     3³  +  3!/3 +  1    = 30
     9 + 1 + 5!/3!       = 30
     15³/5³  + 1 + 3! / 3 = 30





2 4 2
but there are only 3 places not 5
2015-04-22T11:49:19+05:30
This question is not valid because by using odd numbers to fill odd no of dash (3 in this case) always give a odd output and as the question is to makke 30 which is even so it is not possible.
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