Answers

2014-05-01T13:46:32+05:30
xdx+ydy= \frac{a^2(xdy-ydx)}{x^2}+y^2
integrating on both sides
 \frac{x^2}{2}+ \frac{y^2}{2}=a^2( \frac{y}{x} )+ \frac{y^3}{3}+c
where c is an arbitary constant
Note:
 \frac{d}{dx}( \frac{y}{x}) = \frac{xdy-ydx}{x^2}
0
question is solve xdx+ydy={a^2(xdy-ydx)}/(x^2+y^2) by equations reducible to exact equations
ok then don't need arbitrary constant thats it