Answers

2014-05-01T15:46:52+05:30
Well it is normal distribution question
mean=5000 
S.D=1300
n=25
X is random variable
and X=5400
Z=X-mean/S.D=(5400-5000)/1300=4/13=0.31
so for Probablilty
P(X>5400)=0.5-P(0.31>Z>0)=0.3783


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2014-05-01T16:01:50+05:30
Probability for given que is 0.3783

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