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Suneel completes a work in 4 days where as Dinesh completes the work in 6 days,Ramesh works one and half times as fast as Suneel how many days it will take for the three together to complete the work?

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Productivity of Suneel per day: 1/4

Productivity of Dinesh per day : 1/6

productivity of Ramesh per day: 1.5 * 1/4 = 3/8

Total productivity of all = 1/4 + 1/6 + 3/8 per day

= 19/24

So all of them together will finish the complete work in 24/19 days.

Productivity of Dinesh per day : 1/6

productivity of Ramesh per day: 1.5 * 1/4 = 3/8

Total productivity of all = 1/4 + 1/6 + 3/8 per day

= 19/24

So all of them together will finish the complete work in 24/19 days.

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Suneel's 1 day's work=1/4

Dinesh's 1 day's work=1/6

Since Ramesh is 3/2 times faster than Dinesh,

Ramesh's 1 day's work=1/4*3/2=3/8

Working together, part of work done by them in 1 day=1/4+1/6+3/8

=(6+4+9)/24

=19/24.

Therefore they all will complete the work in 1/(19/24) days ,i.e.

__24/19 days__

Dinesh's 1 day's work=1/6

Since Ramesh is 3/2 times faster than Dinesh,

Ramesh's 1 day's work=1/4*3/2=3/8

Working together, part of work done by them in 1 day=1/4+1/6+3/8

=(6+4+9)/24

=19/24.

Therefore they all will complete the work in 1/(19/24) days ,i.e.