Answers

2014-05-01T17:13:47+05:30
Take 2^x-x-1=0 \\ 2^x=x+1
put x=1
2=2 hence 1 is root of the equation
then put
x=0
1=1
hence 1 is also a root
so x=1,0
0
2014-05-01T21:11:01+05:30
Put x=0 in the above equation then 2^0-0-1=0
1-0-1=0
0=0
now put x=1 in the above equation then 2^1-1-1=0
2-1-1=0
2-2=0
0=0
put x=2
2^2-2-1=0
4-2-1=0
2-1=0
1!=0
hence 0 and 1 are roots for the given equation
0